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fix(ipvanish): update openvpn zip file url for updater

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This commit is contained in:
Quentin McGaw
2024-11-07 20:18:29 +00:00
parent 86d82c1098
commit 5f182febae
2 changed files with 2 additions and 2 deletions
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2
internal/provider/ipvanish/updater/servers.go
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@@ -16,7 +16,7 @@ import (
func (u *Updater) FetchServers(ctx context.Context, minServers int) ( func (u *Updater) FetchServers(ctx context.Context, minServers int) (
servers []models.Server, err error, servers []models.Server, err error,
) { ) {
const url = "https://configs.ipvanish.com/configs/configs.zip" const url = "https://configs.ipvanish.com/openvpn/v2.6.0-0/configs.zip"
contents, err := u.unzipper.FetchAndExtract(ctx, url) contents, err := u.unzipper.FetchAndExtract(ctx, url)
if err != nil { if err != nil {
return nil, err return nil, err

2
internal/provider/ipvanish/updater/servers_test.go
View File

@@ -194,7 +194,7 @@ func Test_Updater_GetServers(t *testing.T) {
ctx := context.Background() ctx := context.Background()
unzipper := common.NewMockUnzipper(ctrl) unzipper := common.NewMockUnzipper(ctrl)
const zipURL = "https://configs.ipvanish.com/configs/configs.zip" const zipURL = "https://configs.ipvanish.com/openvpn/v2.6.0-0/configs.zip"
unzipper.EXPECT().FetchAndExtract(ctx, zipURL). unzipper.EXPECT().FetchAndExtract(ctx, zipURL).
Return(testCase.unzipContents, testCase.unzipErr) Return(testCase.unzipContents, testCase.unzipErr)